# Quadratic formula solver

## (The second of three ways to solve (find the roots) of quadratics)

`x=(-b+-sqrt(b^2-4ac))/(2a)`

The negative boy story

A **negative boy** (`-b` )** couldn't decide** (`+-` ) whether to go to a radical **party** (`sqrt` ) but being **square** (`b^2` ) he decided **not** to go (`-` ). He missed out on **four** (`4` )** a**mazing (`a` ) **c**hicks (`c` ). The party was not** over** ( ______ ) until **2a**m (`2a` ).

Given any quadratic equation `ax^2+bx+c=0`

we can substitute the values of `a` , `b` , & `c` into the following formula and solve

`x=(-b+-sqrt(b^2-4ac))/(2a)`

# Quadratic formula solver

## (The second of three ways to solve (find the roots) of quadratics)

`x=(-b+-sqrt(b^2-4ac))/(2a)`

The negative boy story

A **negative boy** (`-b` )** couldn't decide** (`+-` ) whether to go to a radical **party** (`sqrt` ) but being **square** (`b^2` ) he decided **not** to go (`-` ). He missed out on **four** (`4` )** a**mazing (`a` ) **c**hicks (`c` ). The party was not** over** ( ______ ) until **2a**m (`2a` ).

Given any quadratic equation `ax^2+bx+c=0`

we can substitute the values of `a` , `b` , & `c` into the following formula and solve

`x=(-b+-sqrt(b^2-4ac))/(2a)`