## (The second of three ways to solve (find the roots) of quadratics)

x=(-b+-sqrt(b^2-4ac))/(2a)

The negative boy story

A negative boy (-b  ) couldn't decide (+-  ) whether to go to a radical party (sqrt ) but being square (b^2 ) he decided not to go (- ). He missed out on four (4 ) amazing (a ) chicks (c ). The party was not over (  ______  ) until 2am (2a ).

Given any quadratic equation   ax^2+bx+c=0

we can substitute the values of a , b , & c  into the following formula and solve

x=(-b+-sqrt(b^2-4ac))/(2a)