Transformer examples
Now we know
V1V2=Number turns 1Number turns 2
and
V1×I1=V2×I2
We can now work out many problems.
Example 1
A transformer converts 40 volts of alternating current to a higher voltage. The current in the primary coil is 12 amps and the secondary side is 4 amps.
Question A – What is the secondary voltage?
So if we write out all the formulae:
V1V2=Number turns 1Number turns 2.......1
V1×I1=V2×I2........2
using formula 2 we have:
40×12=V2×4
therefore
V2=40×124=120 volts
There are 120 volts produced in the secondary side.
Question B – If there are 100 primary coils, how many secondary coils are there?
Using formula 1 we have:
40120=100Numer turns 2
Turns 2=100×12040
Turns 2=100×3
Turns 2=300
There are 300 turns on the secondary side.
Example 2
A transformer is 100% efficient. It has 200 turns on the primary coil and an input current of 0.5amps. If the secondary coil has 3,000 turns what is the output current?
We know
V1V2=N1N2
and also
V1 I1=V2 I2
Therfore
V1V2=I2I1
and therefore
I2I1=N1N2
Using this last formula we get
I20.5amps=200 turns3000 turns
I2=200×0.53000
I2=0.033.3 amps
The output current is 0.033.3 amps
Example 3
An AC power supply is connected to a transformer. The AC power supply is 12 volts and 2.5 amps. The secondary coil gives a reading of 4 volts.
i. Calculate the power input to the transformer.
We know Power = Village Idiot (see mnemonic)
P=VI
Therefore
P=12×2.5=30 watts
ii. Calculate the current in the secondary coil.
We know power cannot be lost or gained
Voltage 1×Current 1 = Primary power = Secondary power = Voltage 2× Current 2
V1 I1=V2 I2
12×2.5=4×I2
I2=12×2.54
I2=7.5 amps
iii. The primary coil has 15 turns; how many turns does the secondary coil have?
We know
V1V2=N1N2
124=15N2
N2=15×412
N2=5 turns



