Mammoth Memory

Transformer examples

Now we know 

V1V2=Number turns 1Number turns 2

and

V1×I1=V2×I2

We can now work out many problems.

 

Example 1

A transformer converts 40 volts of alternating current to a higher voltage. The current in the primary coil is 12 amps and the secondary side is 4 amps.

Question A – What is the secondary voltage?

So if we write out all the formulae:

V1V2=Number turns 1Number turns 2.......1

V1×I1=V2×I2........2

 

using formula 2 we have:

40×12=V2×4

therefore

V2=40×124=120 volts

There are 120 volts produced in the secondary side.

 

Question B – If there are 100 primary coils, how many secondary coils are there?

Using formula 1 we have:

40120=100Numer turns 2

Turns 2=100×12040

Turns 2=100×3

Turns 2=300

There are 300 turns on the secondary side.

 

Example 2

A transformer is 100% efficient. It has 200 turns on the primary coil and an input current of 0.5amps. If the secondary coil has 3,000 turns what is the output current?

We know

V1V2=N1N2

and also

V1 I1=V2 I2

Therfore

V1V2=I2I1

and therefore

I2I1=N1N2

Using this last formula we get

I20.5amps=200 turns3000 turns

I2=200×0.53000

I2=0.033.3 amps

The output current is 0.033.3 amps

 

Example 3

An AC power supply is connected to a transformer. The AC power supply is 12 volts and 2.5 amps. The secondary coil gives a reading of 4 volts.

i.  Calculate the power input to the transformer.

We know Power = Village Idiot (see mnemonic)

P=VI

Therefore

P=12×2.5=30 watts

 

ii.  Calculate the current in the secondary coil. 

We know power cannot be lost or gained

Voltage 1×Current 1 = Primary power = Secondary power = Voltage 2× Current 2

 

V1 I1=V2 I2

12×2.5=4×I2

I2=12×2.54

I2=7.5 amps

 

iii.  The primary coil has 15 turns; how many turns does the secondary coil have?

 

We know

V1V2=N1N2

124=15N2

N2=15×412

N2=5 turns