Simple interest
Simple interest is the amount of interest paid and it is simply the same every time.
SIMPLE INTEREST = SIMPLY THE SAME
Simple interest `=prt`
Where: | `p=` | The beginning amount |
`r=` | The interest rate (expressed as a decimal) | |
`t=` | Time (in years or time period) |
To remember the formula of simple interest:
Simply I'm pretty
(Simple interest `=prt`)
Example 1
Mrs Jones borrows £50,000 from the bank for one year at a simple interest rate of 5%. How much interest does she pay?
Simple interest `=prt`
Simple interest `=50,000times0.05times1year`
Simple interest `=£2,500`
Answer: Mrs Jones pays £2,500 interest
NOTE:
An alternative to this is just to use logic.
(see our work on percentages to help)
`£50,000` | `=` | `100%` |
`x` | `=` | `5%` |
`(50,000)/x` | `=` | `100/5` |
Multiply by `x` to get `x` on its own.
`(xtimes50,000)/x=(100timesx)/5`
`50,000=20x`
Divide both sides by 20 to get `x` on its own.
`(50,000)/20` | `=` | `(cancel20x)/cancel20` |
`x` | `=` | `(50,000)/20` |
`x` | `=` | `£2,500` |
Example 2
A loan is taken out for `£6,000` for 3 years at `7.5%` simple interest what is the total amount to pay back to the loan company?
First work out the simple interest
Simple interest `=prt`
Simple interest `=6,000times0.075times3year`
Simple interest `=£1,350`
The original sum borrowed `=£6,000`
Therefore the total to pay back `=£1,350+£6,000`
`=£7,350`
NOTE:
An alternative to this is just to use logic.
(see our work on percentages to help)
Work out interest for one year
`£6,000` | `=` | `100%` |
`x` | `=` | `7.5%` |
`(6,000)/x` | `=` | `100/7.5` |
Multiply by `x` to get `x` on its own.
`(xtimes6,000)/x=(100timesx)/7.5`
`6,000=(100x)/7.5`
Multiply both sides by `7.5` to get `x` on its own.
`6,000times7.5` | `=` | `(100xtimescancel7.5)/cancel7.5` |
`6,000times7.5` | `=` | `100x` |
Divide both sides by `100` to get `x` on its own.
`(6,000times7.5)/100` | `=` | `(cancel100\x)/cancel100` |
`x` | `=` | `(6,000times7.5)/100` |
`x` | `=` | `60times7.5` |
`x` | `=` | `£450` (This is for one year) |
For 3 years: `£450times3=£1,350`
The original sum borrowed was `=£6,000`
Therefore the total to pay back `=£1,350+6,000=£7,350`
Example 3
Bernard invests `£420` into a simple interest account which gives 3% interest per annum. What is the interest Bernard earns in 4 years?
Simple interest `=prt`
Simple interest `=420times0.03times4years`
Simple interest `=£50.40`
Alternatively, we could work it out using simple logic.
(see our work on percentage to help)
Work out interest for one year
`£420` | `=` | `100%` |
`x` | `=` | `3%` |
`420/x` | `=` | `100/3` |
Multiply both sides by `x` to get `x` on its own.
`(cancelxtimes420)/cancelx=(100timesx)/3`
`420=(100x)/3`
Multiply both sides by `3` to get `x` on its own.
`420times3` | `=` | `(100xtimescancel3)/cancel3` |
`420times3` | `=` | `100x` |
Divide both sides by `100` to get `x` on its own.
`(420times3)/100` | `=` | `(cancel100\x)/cancel100` |
`x` | `=` | `(420times3)/100` |
`x` | `=` | `4.2times3` |
`x` | `=` | `£12.60` (for one year) |
For four years this `=4times£12.60=£50.40`
Example 4
A bank lent `£1,400` for 4 years at a simple interest rate. Monique paid `£150` in interest, what was her interest rate?
Simple interest `=prt`
`£150` | `=` | `1400times\r\times4years` |
`150` | `=` | `1400times\r\times4` |
`150` | `=` | `5600timesr` |
`r` | `=` | `150/5600` |
`r` | `=` | `0.027` |
If `100%=1`
`x=0.027`
(you need our work on percentages to work this out)
`100/x` | `=` | `1/0.027` |
`x` | `=` | `100times0.027` |
`x` | `=` | `2.7%` |