Charles' Law In Use
We know that in Charles' law
V1T1=V2T2
NOTE: Pressure remains constant
Also, if you put a balloon inside a bucket and pour cold liquid nitrogen over the balloon, you can watch it shrink.
This is Charles' Law
V1 and T1 refer to the volume and temperature before you pour the liquid nitrogen on the balloon and V2 and T2 refer to the volume and temperature after you pour the liquid nitrogen on the balloon.
Reduce the temperature of the gas and the volume of the gas reduces too.
Reducing the temperature of a gas slows down the molecules and they have less energy (kinetic energy) to hit and push the sides of the balloon. The molecules will exert less force and so the external atmospheric pressure will collapse the balloon.
NOTE 1:
The standard unit used to measure volume is m3 (metre cubed)
The standard unit used to measure temperature is K (Kelvin)
NOTE 2:
You can use other units for volume such as m3 or ml as long as you use the same units either side of the equation but you must use Kelvin for temperature.
NOTE 3:
Never forget to convert temperature to Kelvin
Temperature in Kelvin = temperature in degrees Celsius ( ∘C)+273
You must always use temperature measured in Kelvin in any gas law equation.
Examples
1. A container holds 50.0 ml of nitrogen at 25∘C and a pressure of 736 mm Hg. What will be its volume if the temperature increases by 35∘C ?
V1T1=V2T2
Therefore V2=V1×T2T1
V1=50 ml
V2=?
T1=25∘C+273=298K
T2=25∘C+35∘C+273=333K
Therefore V2=50×333298
V2=55.9 ml
2. 568 cm3 of chlorine at 25∘C will occupy what volume at -25∘C while the pressure remains constant?
V1T1=V2T2
V1=568 cm3
V2=?
T1=25∘C+273=298K
T2=-25∘C+273=248K
Therefore V2=V1×T2T1
V2=568×248298
V2=473 cm3
3. A sample of hydrogen has an initial temperature of 50∘C. When the temperature is lowered to -5.0∘C, the volume of hydrogen becomes 212 cm3. What was the initial volume of the hydrogen?
V1T1=V2T2
V1=?
V2=212 cm3
T1=50∘C+273=323K
T2=-5∘C+273=268K
Therefore V1=V2×T1T2
V1=212×323268
V1=256 cm3



