Gay-Lussac's Law In Use
We know in Gay-Lussac's law
P1T1=P2T2
NOTE:
Volume remains constant
Also you know that if you put a sealed container in a fire it will make the pressure inside the canister increase.
This is Gay-Lussac's law
P1 and T1 refer to the pressure and temperature before you throw the container in the fire and P2 and T2 refer to the pressure and temperature after you throw the container in the fire.
Increasing the temperature of the gas increases the pressure in the container.
Increasing the temperature of a gas speeds up the molecules and they have more energy (kinetic energy) to hit and push the side of the container. The molecules will exert more pressure.
NOTE 1:
The standard unit used to measure pressure is Pa (Pascals)
The standard unit used to measure temperature is K (Kelvin)
NOTE 2:
You can use other units for pressure such as pounds per square inch or mm of mercury (mm Hg) or atm (atmospheres) as long as you use the same units either side of the equation but you must use Kelvin for temperature.
NOTE 3:
Never forget to convert temperature to Kelvin
Temperature in Kelvin = Temperature in degrees Celsius ( ∘C)+273
You must always use temperature measured in Kelvin in any gas law equation.
Examples
1. A 30 l sample of nitrogen inside a rigid, metal container at 20∘C is placed inside an oven whose temperature is 50∘C. The pressure inside the container at 20∘C was at 3.00 atm. What is the pressure of the nitrogen after its temperature is increased to 50∘C ?
1. A 30 l sample of nitrogen inside a rigid, metal container at 20∘C is placed inside an oven whose temperature is 50∘C. The pressure inside the container at 20∘C was at 3.00 atm. What is the pressure of the nitrogen after its temperature is increased to 50∘C ?
P1T1=P2T2
P1=3atm
P2=?
T1=20∘C+273=293K
T2=50∘C+273=323K
Therefore 3293=P2323
P2=3×323293
P2=3.31atm (to three significant figures)
2. If a gas in a closed container is pressurized from 15 atmospheres to 16 atmospheres and its original temperature was 25∘C, what would the final temperature of the gas be in degrees Celsius?
2. If a gas in a closed container is pressurized from 15 atmospheres to 16 atmospheres and its original temperature was 25∘C, what would the final temperature of the gas be in degrees Celsius?
P1T1=P2T2
P1=15atm
P2=16atm
T1=25∘C+273=298K
T2=?
Therefore 15298=16T2
T2=16×29815
T2=317.9K
But don't forget to convert back from Kelvin to degrees Celsius
Therefore T2=317.9-273=44.9∘C
3. The temperature of a sample of gas in a steel container at 30 kPa is increased from -100∘C to 1.00×103 ∘C. What is the final pressure inside the tank.
3. The temperature of a sample of gas in a steel container at 30 kPa is increased from -100∘C to 1.00×103 ∘C. What is the final pressure inside the tank.
P1T1=P2T2
P1=30 kPa
P2=?
T1=-100∘C+273=173K
T2=1.00×103 ∘C=1000∘C+273=1273K
Therefore P2=P1×T2T1
P2=30×1273173
P2=221 kPa to three significant figures



