Mammoth Memory

Gay-Lussac's Law In Use

We know in Gay-Lussac's law

P1T1=P2T2

NOTE:

Volume remains constant

Also you know that if you put a sealed container in a fire it will make the pressure inside the canister increase.

Gay-Lussac's law if you put a sealed container in a fire it will make the pressure inside the canister increase.

This is Gay-Lussac's law

P1 and T1 refer to the pressure and temperature before you throw the container in the fire and  P2 and T2 refer to the pressure and temperature after you throw the container in the fire.

Increasing the temperature of the gas increases the pressure in the container.

Gay-Lussac's law increasing the temperature of the gas increases the pressure in the container

Increasing the temperature of a gas speeds up the molecules and they have more energy (kinetic energy) to hit and push the side of the container. The molecules will exert more pressure.

NOTE 1:

The standard unit used to measure pressure is Pa (Pascals)

The standard unit used to measure temperature is K (Kelvin)

 

NOTE 2:

You can use other units for pressure such as pounds per square inch or mm of mercury (mm Hg) or atm (atmospheres) as long as you use the same units either side of the equation but you must use Kelvin for temperature.

 

NOTE 3:

Never forget to convert temperature to Kelvin

Temperature in Kelvin = Temperature in degrees Celsius ( C)+273 

You must always use temperature measured in Kelvin in any gas law equation. 

 

Examples

1. A 30 l sample of nitrogen inside a rigid, metal container at 20C is placed inside an oven whose temperature is 50C. The pressure inside the container at 20C was at 3.00 atm. What is the pressure of the nitrogen after its temperature is increased to 50C ?

Reveal answer

1. A 30 l sample of nitrogen inside a rigid, metal container at 20C is placed inside an oven whose temperature is 50C. The pressure inside the container at 20C was at 3.00 atm. What is the pressure of the nitrogen after its temperature is increased to 50C ?

P1T1=P2T2

P1=3atm

P2=?

T1=20C+273=293K

T2=50C+273=323K

Therefore 3293=P2323

P2=3×323293

P2=3.31atm (to three significant figures)

 

 

2. If a gas in a closed container is pressurized from 15 atmospheres to 16 atmospheres and its original temperature was 25C, what would the final temperature of the gas be in degrees Celsius?

Reveal answer

2. If a gas in a closed container is pressurized from 15 atmospheres to 16 atmospheres and its original temperature was 25C, what would the final temperature of the gas be in degrees Celsius?

P1T1=P2T2

P1=15atm

P2=16atm

T1=25C+273=298K

T2=?

Therefore 15298=16T2

T2=16×29815

T2=317.9K

But don't forget to convert back from Kelvin to degrees Celsius

Therefore T2=317.9-273=44.9C

 

3. The temperature of a sample of gas in a steel container at 30 kPa is increased from -100C to 1.00×103 C. What is the final pressure inside the tank.

Reveal answer

3. The temperature of a sample of gas in a steel container at 30 kPa is increased from -100C to 1.00×103 C. What is the final pressure inside the tank.

P1T1=P2T2

P1=30 kPa

P2=?

T1=-100C+273=173K

T2=1.00×103 C=1000C+273=1273K

Therefore P2=P1×T2T1

P2=30×1273173

P2=221 kPa to three significant figures