# Common core division

Common core division is a way of dividing by using multiplication and subtraction instead. It subtracts in small chunks, in easy multiples like 2 or 10 or 100. You keep note of how many lots have been taken away to give the final answer.

Common core division – Take chunks away from the core.

Common core divison = Repeated subtraction

NOTE:

Using this method means there are many different ways to subtract chunks from the division and so no two solutions to the problem will be the same.

Example 1

420div3

 3 4 2 0 3 0 0 100 1 2 0 3 0 10 9 0 3 0 10 6 0 3 0 10 3 0 3 0 10 0 140

To see every step broken down

## Common core division step by step

Example 1

420div3

 3 4 2 0 At first put the 3 in front of a division sign and the 420 inside just as the traditional method.

 3 4 2 0 But unlike the traditional method we subtract easy amounts in small chunks. Such as 3xx100 and keep a running total. 3xx100rArr 3 0 0 100

 3 4 2 0 Take away to give: 3 0 0 100 1 2 0 Take away the300 from the 420

 3 4 2 0 3 0 0 100 1 2 0 Subtract 3xx10 and add 10 to the running total. 3xx10rArr 3 0 10

 3 4 2 0 3 0 0 100 1 2 0 Take away to give: 3 0 10 9 0 Take 30 away from the 120

 3 4 2 0 3 0 0 100 1 2 0 3 0 10 9 0 Subtract 3xx10 again and add to the running total. 3xx10rArr 3 0 10

 3 4 2 0 3 0 0 100 1 2 0 3 0 10 9 0 Take away to give: 3 0 10 6 0 Take 30 away from 90

 3 4 2 0 3 0 0 100 1 2 0 3 0 10 9 0 3 0 10 6 0 Subtract 3xx10 again and add to the running total. 3xx10rArr 3 0 10

 3 4 2 0 3 0 0 100 1 2 0 3 0 10 9 0 3 0 10 6 0 Take away to give: 3 0 10 Take 30 away from 60 3 0

 3 4 2 0 3 0 0 100 1 2 0 3 0 10 9 0 3 0 10 6 0 3 0 10 3 0 Subtract 3xx10 again and add to the running total. 3xx10rArr 3 0 10

 3 4 2 0 3 0 0 100 1 2 0 3 0 10 9 0 3 0 10 6 0 3 0 10 3 0 Now take away the final 30 leaving nothing. Take away to give: 3 0 10 Then add up the running totals on the right. 0 140

420div3=140

420div3=140

Example 2

300div3

 3 3 0 0 3 0 0 100 0 100

To see every step broken down

## Common core division step by step

Example 2

300div3

 3 3 0 0 At first put the 3 in front of a division sign and the 300 inside just as the traditional method.

 3 3 0 0 But unlike the traditional method we subtract easy amounts in small chunks, start with 3xx100=300 and keep a running total on the right. 3xx100rArr 3 0 0 100

 3 3 0 0 Take away to give: 3 0 0 100 Now take away the remainder leaving nothing. So the running total is 100. 0 100

300div3=100

300div3=100

Example 3

3684div24

 24 3 6 8 4 2 4 0 0 100 1 2 8 4 1 2 0 0 50 8 4 4 8 2 3 6 2 4 1 1 2 153

To see every step broken down

## Common core division step by step

Example 3

3684div24

 24 3 6 8 4 At first put the 24 in front of a division sign and the 3684 inside just as the traditional method

 24 3 6 8 4 But unlike the traditional method we subtract easy amounts in small chunks. Start with 24xx100=2400 and keep a running total on the right 100xx24rArr 2 4 0 0 100

 24 3 6 8 4 Take away to give: 2 4 0 0 100 Take 2400 from 3684. 1 2 8 4

 24 3 6 8 4 2 4 0 0 100 1 2 8 4 Subtract 50xx24 and add 50 to the running total. 50xx24rArr 1 2 0 0 50

 24 3 6 8 4 2 4 0 0 100 1 2 8 4 Take away to give: 1 2 0 0 50 Take 1200 from 1284. 8 4

 24 3 6 8 4 2 4 0 0 100 1 2 8 4 1 2 0 0 50 8 4 Subtract 2xx24 and add 2 to the running total. 2xx24rArr 4 8 2

 24 3 6 8 4 2 4 0 0 100 1 2 8 4 1 2 0 0 50 8 4 Take away to give: 4 8 2 3 6 Take 48 from 84 to leave 36.

 24 3 6 8 4 2 4 0 0 100 1 2 8 4 1 2 0 0 50 8 4 4 8 2 3 6 Subtract 1xx24 and add 1 to the running total. 1xx24rArr 2 4 1

 24 3 6 8 4 2 4 0 0 100 1 2 8 4 1 2 0 0 50 8 4 4 8 2 3 6 Take 24 from 36 to leave 12. Take away to give: 2 4 1 Add the running totals on the right. 1 2 153

3684div24=153 remainder 12

3684div24=153 remainder 12

Example 4

4673div15

 15 4 6 7 3 1 5 0 0 100 3 1 7 3 1 5 0 0 100 1 6 7 3 1 5 0 0 100 1 7 3 1 5 0 10 2 3 1 5 1 8 311

To see every step broken down

## Common core division step by step

Example 4

4673div15

 15 4 6 7 3 At first put 15 in front of a division sign and the 4673 inside just as the traditional method.

 15 4 6 7 3 But unlike the traditional method we subtract easy amounts in small chunks. Start with 15xx100=1500 and keep a running total on the right. 15xx100 1 5 0 0 100

 15 4 6 7 3 Take away to give: 1 5 0 0 100 3 1 7 3 Take 1500 away from 4673

 15 4 6 7 3 1 5 0 0 100 Subtract 15xx100 again and add 100 to the running total on the right. 3 1 7 3 15xx100 again 1 5 0 0 100

 15 4 6 7 3 1 5 0 0 100 3 1 7 3 Take away to give: 1 5 0 0 100 Take 1500 away from 3173 1 6 7 3

 15 4 6 7 3 1 5 0 0 100 3 1 7 3 1 5 0 0 100 Subtract 15xx100 again and add 100 to the running total on the right. 1 6 7 3 15xx100 again 1 5 0 0 100

 15 4 6 7 3 1 5 0 0 100 3 1 7 3 1 5 0 0 100 1 6 7 3 Take away to give: 1 5 0 0 100 1 7 3 Take 1500 away from 1673

 15 4 6 7 3 1 5 0 0 100 3 1 7 3 1 5 0 0 100 1 6 7 3 1 5 0 0 100 1 7 3 Subtract 15xx10 and add 10 to the running total on the right. 15xx10 1 5 0 10

 15 4 6 7 3 1 5 0 0 100 3 1 7 3 1 5 0 0 100 1 6 7 3 1 5 0 0 100 1 7 3 Take away to give: 1 5 0 10 Take 150 away from 173 2 3

 15 4 6 7 3 1 5 0 0 100 3 1 7 3 1 5 0 0 100 1 6 7 3 1 5 0 0 100 1 7 3 1 5 0 10 Subtract 15xx1 and add 1 to the running total on the right. 2 3 15xx1 1 5 1

 15 4 6 7 3 1 5 0 0 100 3 1 7 3 1 5 0 0 100 Take 15 from 23 and it leaves 8 which is less than 15, and so is the remainder. 1 6 7 3 1 5 0 0 100 1 7 3 1 5 0 10 Add up the running totals on the right to give the final answer less the remainder. 2 3 Take away to give: 1 5 1 8 311

4673div15=311 remainder 8
4673div15=311 remainder 8