Using the standard deviation formula
The standard deviation formula is:
Standard deviation =σ=√Σ(x-ˉx)2n-1
For any set of values to find the standard deviation you should:
1. Find the mean (of all the numbers) =ˉx
2. Subtract the mean (from each number) =x-ˉx
3. Square the result (of each of the above) =(x-ˉx)2
4. Add the results up (Add) =∑(x-ˉx)2
5. Divide (the result) by the number of data values minus one =∑(x-ˉx)2n-1
6. Take the square root of the result =√∑(x-ˉx)2n-1
Example 1
What is the standard deviation for the following set of data?
15, 15, 15, 14, 16
The process is as follows:
i. Find the mean: 15+15+15+14+165=755=15
ii Subtract the mean from each of the data points:
15-15 |
15-15 |
15-15 |
14-15 |
16-15 |
0 |
0 |
0 |
-1 |
1 |
iii. Square the result:
02=0 |
02=0 |
02=0 |
-12=1 |
12=1 |
iv. Add the results up:
0+0+0+1+1=2
v. Divide by the number of data points less one.
Therefore 25-1=24=0.5
vi. Square root the result:
√0.5=0.707
Answer:
The standard deviation for the above data = 0.707
That is 68% of all the data is within 0.707 of 15.
Example 2
What is the standard deviation for the following set of data?
2, 7, 14, 22, 30.
The process is as follows:
i. Find the mean: 2+7+14+22+305=755=15
ii. Subtract the mean from each of the data points:
2-15 | 7-15 | 14-15 | 22-15 | 30-15 |
-13 | -8 | -1 | 7 | 15 |
iii. Square the result:
-132=169 | -82=64 | -12=1 | 72=49 | 152=225 |
iv. Add the results up:
169+64+1+49+225=508
v. Divide by the number of data points less one.
5085-1=5084=127
vi. Square root the result:
√127=11.3
Answer:
The standard deviation for the above set of data = 11.3
That is 68% of all the data is within 11.3 of 15.



