Difficult examples
1. Simplify
`4/sqrt8`
The first thing you should attempt is to rationalise the denominator.
`4/sqrt8=4/{sqrt8timessqrt8/sqrt8}=4/{{sqrt8timessqrt8}/sqrt8}=4/{{8}/sqrt8}`
So we have rationalised the denominator
i.e.
`4/sqrt8=4/(8/sqrt8)`
But we can go further
`4/{{8}/{sqrt8}}={4timessqrt8}/8=sqrt8/2`
But now we can also simplify square roots
Simplify `sqrt8`
Write down what we know
`2=sqrt4,\ \ \ \ 3=sqrt9,\ \ \ \ 4=sqrt16`
`5=sqrt25,\ \ 6=sqrt36,\ \ 7=sqrt49`
`sqrt8=sqrt(4times2)`
Try something we know using `sqrt9`
`sqrt(9times4)=sqrt36=6`
Is that the same as
`sqrt9timessqrt4=3times2=6`
Yes it is
Therefore `sqrt(4times2)=sqrt4timessqrt2`
`sqrt4timessqrt2=2timessqrt2`
To finish
`sqrt8/2=(cancel2timessqrt2)/cancel(2)=sqrt2`
Answer: `4/sqrt8=sqrt2`
2. Simplify `sqrt(a^3)`
Try something we know using `sqrt9`
We know `sqrt(9^2)` is the same as
`sqrt9timessqrt9`
i.e. both = 9
Therefore `sqrt(9^3)=sqrt9timessqrt9timessqrt9`
Is the same as
`=sqrt(9^2)timessqrt9=9sqrt9`
Therefore `=sqrt(a^3)`
Is the same as
`=sqrt(a^2)timessqrta=asqrta`
Answer: `sqrt(a^3)=asqrta`
3. Rationalise the denominator
`2/(9sqrt5)`
Rationalise the denominator = Turn the surd of the denominator into a fraction.
`2/{9sqrt5}=2/{{9timessqrt5timessqrt5}/sqrt5}=2/{{9times5}/sqrt5}=2/{45/sqrt5}`
We have rationalised the denominator but we can go further
`2/{{45}/sqrt5}={2sqrt5}/45`
Answer: `2/{9sqrt5}={2sqrt5}/45`
4. Simplify
`(3+sqrt2)(3-sqrt2)`
Multiply out
`=3times3+3times(-sqrt2)+3timessqrt2-sqrt2timessqrt2`
`=9-3sqrt2+3sqrt2 -sqrt(2times2)`
`=9-cancel(3sqrt2)+cancel(3sqrt2) -sqrt4`
`=9-2`
`= 7`
Answer: = 7
5. Simplify
`(x+sqrty)^2`
Multiply out
Answer:
`=x^2+xsqrty+xsqrty+sqrtytimessqrty`
`=x^2+2xsqrty+sqrtytimessqrty`
`=x^2+2xsqrty+sqrt(y^2)`
`=x^2+2xsqrty+y`
Answer: `=x^2+2xsqrty+y`
6. Simplify
`(x+sqrty)(x-sqrty)`
Multiply out
`=x^2-xsqrty+xsqrty-sqrtytimessqrty`
`=x^2-cancel(xsqrty)+cancel(xsqrty)-sqrt(y^2)`
`=x^2-y`
Answer: `=x^2-y`
7. Simplify
`6sqrt2+sqrt18`
First simplify
`sqrt18`
Write down what we know
`2=sqrt4,\ \ \ \ 3=sqrt9,\ \ \ \ 4=sqrt16`
`5=sqrt25,\ \ 6=sqrt36,\ \ 7=sqrt49`
The biggest square that divides into 18 is 9.
Therefore `sqrt18 = sqrt(2times9)`
Try something we know using `sqrt9`
`sqrt(4times9)=sqrt36=6`
Is that the same as
`sqrt4timessqrt9=3times2=6`
Yes it is
Therefore `sqrt(2times9)=sqrt2timessqrt9`
`sqrt2timessqrt9=3timessqrt2`
So now getting back to the original question
`6sqrt2+sqrt18`
`=6sqrt2+3sqrt2`
Try something we know using `sqrt9`
`6sqrt9+3sqrt9=6times3+3times3`
`=18+9=27`
Is that the same as
`(6+3)sqrt9=9sqrt9=9times3=27`
Yes it is
Therefore `6sqrt2+3sqrt2`
`=(6+3)sqrt2`
`=9sqrt2`
Answer: `6sqrt2+sqrt18=9sqrt2`
8. Simplify
`8sqrt10times5sqrt15`
`8timessqrt10times5timessqrt15`
`8times5timessqrt10timessqrt15`
`40sqrt15timessqrt10`
Try something we know using `sqrt9`
`sqrt9 timessqrt4=3times2=6`
Is that the same as
`sqrt(9 times4)=sqrt36=6`
Yes it is
Therefore `40sqrt15timessqrt10`
`=40timessqrt(15times10)`
`=40sqrt150`
So now simplify
`sqrt150`
Write down what we know
`2=sqrt4,\ \ \ 3=sqrt9,\ \ \ \ \ \ 4=sqrt16`
`5=sqrt25,\ \ 6=sqrt36,\ \ \ 7=sqrt49`
`8=sqrt64,\ \ 9=sqrt81,\ \ 10=sqrt100`
The biggest square that divides into 150 = 25.
Therefore `sqrt150=sqrt(3times25)=sqrt3timessqrt25`
`sqrt3timessqrt25=5sqrt3`
Get back to
`40sqrt150`
This now equals
`40times5sqrt3`
Therefore `200sqrt3`
Answer: `8sqrt10times5sqrt15=200sqrt3`
9. Simplify
`(5sqrt6+4sqrt3)(3sqrt6-2sqrt3)`
First multiply out the brackets
`5sqrt6times3sqrt6-2sqrt3times5sqrt6+4sqrt3times3sqrt6-2sqrt3times4sqrt3`
Working on BIDMAS
Stage 1
Work out `5sqrt6times3sqrt6`
Try something we know using `sqrt9`
`5sqrt9times3sqrt9=5times3times3times3`
`=15times9`
Is that the same as
`5times3timessqrt(9times9)=5times3timessqrt81`
`=15times9`
Yes it is
Therefore `5timessqrt6times3timessqrt6`
`=5times3timessqrt6timessqrt6`
`=15sqrt36`
`=15times6`
`=90`
Stage 2
Work out `-2sqrt3times5sqrt6`
Try something we know using `sqrt9`
`-2timessqrt9times5timessqrt4`
`=-2times3times5times2`
`=-6times10=-60`
Is this the same as
`-2times5timessqrt(9times4)`
`=-10timessqrt36`
`=-10times6=-60`
Yes it is
Therefore `-2timessqrt3times5timessqrt6`
`=-2times5timessqrt3timessqrt6`
`=-10timessqrt(3times6)`
`=-10timessqrt18`
But we can simplify
`sqrt18`
Write down what we know
`2=sqrt4`, `3=sqrt9`, `4=sqrt16`
Therefore `sqrt18=sqrt(9times2)=sqrt9timessqrt2`
`sqrt18=3timessqrt2`
Going back
Therfore `-10timessqrt18`
`-10times3timessqrt2`
`-30sqrt2`
Stage 3
`4sqrt3times3sqrt6`
As stage 2
`4timessqrt3times3timessqrt6`
`4times3timessqrt3times sqrt6`
`12timessqrt3timessqrt6`
`12timessqrt(3times6`
`12timessqrt18`
We know from stage 2
`sqrt18=3timessqrt2`
Therefore `12timessqrt18=12times3timessqrt2=36sqrt2`
Stage 4
`-2sqrt3times4sqrt3`
As stage 2
`-2timessqrt3times4timessqrt3`
`-2times4timessqrt3timessqrt3`
`-8timessqrt(3times3)`
`-8timessqrt9`
`-8times3`
`-24`
Putting all the stages together:
`90-30sqrt2+36sqrt2-24`
`90+6sqrt2-24`
`90-24+6sqrt2`
`66+6sqrt2`
Answer: `(5sqrt6+4sqrt3)(3sqrt6-2sqrt3)`
`=66+6sqrt2`