Quadratic formula solver

(The second of three ways to solve (find the roots) of quadratics)

$x=(-b+-sqrt(b^2-4ac))/(2a)$

The negative boy story

The second of three ways to solve quadratic equations

A negative boy ( $-b$ ) couldn't decide ( $+-$ ) whether to go to a radical party ( $sqrt$ ) but being square ( $b^2$ ) he decided not to go ( $-$ ). He missed out on four ( $4$ ) amazing ( $a$ ) chicks ( $c$ ). The party was not over ( ______ ) until 2am ( $2a$ ).

Given any quadratic equation $ax^2+bx+c=0$

we can substitute the values of $a$ , $b$ , & $c$ into the following formula and solve

$x=(-b+-sqrt(b^2-4ac))/(2a)$