Quadratic formula solver

(The second of three ways to solve (find the roots) of quadratics)

`x=(-b+-sqrt(b^2-4ac))/(2a)`

The negative boy story

The second of three ways to solve quadratic equations

A negative boy (`-b` ) couldn't decide (`+-` ) whether to go to a radical party (`sqrt` ) but being square (`b^2` ) he decided not to go (`-` ). He missed out on four (`4` ) amazing (`a` ) chicks (`c` ). The party was not over ( ______ ) until 2am (`2a` ).

Given any quadratic equation `ax^2+bx+c=0`

we can substitute the values of `a` , `b` , & `c` into the following formula and solve

`x=(-b+-sqrt(b^2-4ac))/(2a)`