Using the quadratic formula solver Example 1

Solve $3x^2-7x+2=0$

Use the quadratic formula solver

$x=(-b+-sqrt(b^2-4ac))/(2a)$

Therefore $a=3$ , $b=-7$ , & $c=2$

$x=(-(-7)+-sqrt((-7)^2-4times3times2))/(2times3)$

$x=(7+-sqrt(49-24))/6=(7+-sqrt25)/6=(7+-5)/6$

$x=12/6$ and $x=2/6$

$x=2$ and $x=1/3$

So $x=2$ and $1/3$ is the answer.

$3x^2-7x+2=0$

If $x=2$ $3times2^2-7times2+2=0$

$12-14+2=0$ Which is correct

If $x=1/3$ $3times(1/3)^2-7times(1/3)+2=0$

$3/9-7/3+2=0$

$1/3-2\1/3+2=0$ Which is correct

(If they don't add up to zero you can be assured that it is wrong).

Answer:

The roots of $3x^2-7x+2=0$ are $x=2$ or $1/3$

Quick stetch example 1