Using the quadratic formula solver Example 2

Solve $x^2-6x+8=0$

$x=(-b+-sqrt(b^2-4ac))/(2a)$

Therefore $a=1$ , $b=-6$ & $c=8$

$x=(-(-6)+-sqrt((-6)^2-4times1times8))/(2times1)$

$x=(6+-sqrt(36-32))/2$

$x=(6+-sqrt4)/2$

$x=(6+-2)/2$

$x=(6+2)/2$ or $x=(6-2)/2$

$x=8/2$ or $x=4/2$

$x=4$ or $2$

$x^2-6x+8=0$

If $x=4$ $4^2-6times4+8=0$

$16-24+8=0$ Which is correct

If $x=2$ $2^2-6times2+8=0$

$4-12+8=0$ Which is correct

Answer:

The roots of $x^2-6x+8=0$ are $x=4$ and $x=2$

Quick stetch example 2