Indices examples
Example 1
What is `2^0` in a simpler form?
Answer:
We have two ways to remember this
Method 1
Remember the picture "it doesnt matter how many people there are there is only one sun" which means
`2^0` is therefore `=1`
or
Method 2
Try simple numbers you know first
`(10^2)/(10^2)=100/100=1`
and also
`(10^2)/(10^2)=10^2times10^-2=10^0` must`=1`
therefore `2^0=1`
Example 2
What is `49^(-1/2)` in a simpler form?
Answer:
Try simpler numbers we know first
We know
`10^-2=1/(10^2)`
so
`49^(-1/2)=1/(49^(1/2))`
and we also know the `1/2` denotes that it is root `2`.
So
`49^(1/2)` is `sqrt49`
and
`sqrt49=7`
Therfore
`1/49^(1/2)=1/sqrt49=1/7`
So the answer `=1/7`
Example 3
What is `64^(1/3)` in a simpler form
Answer:
Method 1
`64^(1/3)` actually reads
Work out what we multiply by itself `3` times to get `64`
Which would be `xtimesxtimesx=64`
this is `4times4times4=64`
Therefore `64^(1/3)=4`
Method 2
Try simpler numbers you know
You might recognise that
`9^(1/2)=sqrt9=3`
and
`27^(1/3)=root(3)(27)=3`
Therefore
`64^(1/3)=root(3)(64)=4`
Example 4
What is `1^9`
Answer:
Try simpler numbers you know
We know
`2^2=2times2=4`
Therefore
`1^9=1times1times1times1times1times1times1times1times1`
`=1`
Therefore
`1^9=1`
Example 5
What is `(1\2/5)^3`
Answer:
The first thing to do is turn
`1\2/5` into a fraction
See mammoth memory fractions
`1\2/5=7/5`
So `(1\2/5)^3` becomes `(7/5)^3`
"Try simple numbers you know first"
Try `(4/2)^3=2^3=2times2times2=8`
is this the same as
`4^3/2^3=(4times4times4)/(2times2times2)`
`=(cancel4\ ^2timescancel4\ ^2timescancel4\ ^2)/(cancel2timescancel2timescancel2)`
`=2times2times2=8`
Yes it is
Therefore
`(7/5)^3=7^3/5^3`
`=(7times7times7)/(5times5times5)`
`=343/275`
`1.247` to `3` decimal places.
Example 6
What is `16^(3/2)`
To tackle this we "always split the power into a root and a power"
`16^(3/2)=` either `(16^3)^(1/2)` or `(16^(1/2))^3`
Lets go for
`(16^(1/2))^3`
Which is `(root(2)(16))^3`
Which is `4^3`
and this is `4times4times4`
`=16times4`
`=64`
Example 7
Simplify `(4x^-2)/y^0`
We must remember the picture
"It doesn't matter how many people there are there is only one sun" which means
`y^0=1`
Therefore
`(4x^-2)/y^0`
`= (4x^-2)/1`
Which is just `4x^-2`
But "trying a simpler number we know first"
`10^-2=1/(10^2)`
Therefore
`4x^-2`
is the same as
`4/x^2`
Example 8
Simplify `18x^4y^5div3xy^4`
This would be the same as
`(18x^4y^5)/(3xy^4)`
and can be re-written as
`(18timesxtimesxtimesxtimesxtimesytimesytimesytimesytimesy)/(3xtimesytimesytimesytimesy)`
and if we cancel out we get
`(18timesxtimesxtimesxtimescancelxtimesytimescancelytimescancelytimescancelytimescancely)/(3timescancelxtimescancelytimescancelytimescancelytimescancely)`
`=(18timesxtimesxtimesxtimesy)/3`
`=(18x^3y)/3`
Or
`6x^3y`